What is the answer to log_{3}(4x^3+14x^2+13x+3)=log_{3}(x+1) ?

The answer to log_{3}(4x^3+14x^2+13x+3)=log_{3}(x+1) is x=(-5+sqrt(17))/4

Solve for x: log_{3}(4x^3+14x^2+13x+3)=log_{3}(x+1)

The solution is x=(-5+sqrt(17))/4

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lo g_{3} (4 x^{3} + 14 x^{2} + 13 x + 3) = lo g_{3} (x + 1)

x = \frac{- 5 + 17}{4}

Decimal Notation

x = - 0.21922 \dots

Solution steps

lo g_{3} (4 x^{3} + 14 x^{2} + 13 x + 3) = lo g_{3} (x + 1)

Apply log rules

4 x^{3} + 14 x^{2} + 13 x + 3 = x + 1

Solve

4 x^{3} + 14 x^{2} + 13 x + 3 = x + 1 : x = - 1, x = \frac{- 5 + 17}{4}, x = \frac{- 5 - 17}{4}

x = - 1, x = \frac{- 5 + 17}{4}, x = \frac{- 5 - 17}{4}

Verify Solutions:

x = - 1

False

, x = \frac{- 5 + 17}{4}

True

, x = \frac{- 5 - 17}{4}

False

The solution is

x = \frac{- 5 + 17}{4}

lo g_{10} (8 x) = \frac{7}{3}

ln (x + 5) - ln (x) = 3

lo g_{10} (n) = - 0.1302

ln (4 x - 2) = 5

lo g_{5} (x - 5) = 4

What is the answer to log_{3}(4x^3+14x^2+13x+3)=log_{3}(x+1) ?
The answer to log_{3}(4x^3+14x^2+13x+3)=log_{3}(x+1) is x=(-5+sqrt(17))/4
Solve for x: log_{3}(4x^3+14x^2+13x+3)=log_{3}(x+1)
The solution is x=(-5+sqrt(17))/4