What is the answer to log_{10}(n)=-0.1302 ?

The answer to log_{10}(n)=-0.1302 is n= 1/(10^{0.1302)}

Solve for n: log_{10}(n)=-0.1302

The solution is n= 1/(10^{0.1302)}

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lo g_{10} (n) = - 0.1302

n = \frac{1}{1 0 ^{0.1302}}

Decimal Notation

n = 0.74096 \dots

Solution steps

lo g_{10} (n) = - 0.1302

Apply log rules

n = \frac{1}{1 0 ^{0.1302}}

ln (4 x - 2) = 5

lo g_{5} (x - 5) = 4

ln (x) = - 3

lo g_{10} (x) = 12304

lo g_{2} (x) + lo g_{2} (x + 6) = 4

What is the answer to log_{10}(n)=-0.1302 ?
The answer to log_{10}(n)=-0.1302 is n= 1/(10^{0.1302)}
Solve for n: log_{10}(n)=-0.1302
The solution is n= 1/(10^{0.1302)}