What is the answer to log_{2}(x)+log_{2}(x+6)=4 ?

The answer to log_{2}(x)+log_{2}(x+6)=4 is x=2

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log_{2}(x)+log_{2}(x+6)=4

lo g_{2} (x) + lo g_{2} (x + 6) = 4

x = 2

Solution steps

lo g_{2} (x) + lo g_{2} (x + 6) = 4

Apply log rules

x (x + 6) = 16

Solve

x (x + 6) = 16 : x = 2, x = - 8

x = 2, x = - 8

Verify Solutions:

x = 2

True

, x = - 8

False

The solution is

x = 2

lo g_{\frac{1}{2}} (x) = 3

a, ln (8 a) = ln (a + 2 b) - ln (b)

x, (b) \cdot y = ln (x^{2})

n = lo g_{10} (d) 150012

(lo g_{10} (x))^{2} - lo g_{10} (x) - 2 = 0

What is the answer to log_{2}(x)+log_{2}(x+6)=4 ?
The answer to log_{2}(x)+log_{2}(x+6)=4 is x=2
Solve for x: log_{2}(x)+log_{2}(x+6)=4
The solution is x=2