What is the answer to solvefor a,ln(8a)=ln(a+2b)-ln(b) ?

The answer to solvefor a,ln(8a)=ln(a+2b)-ln(b) is a=(2b)/(8b-1) {b> 1/8 }

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solvefor a,ln(8a)=ln(a+2b)-ln(b)

solve for

a, ln (8 a) = ln (a + 2 b) - ln (b)

a = \frac{2 b}{8 b - 1} {b > \frac{1}{8}}

Solution steps

ln (8 a) = ln (a + 2 b) - ln (b)

Add

ln (b)

to both sides

ln (8 a) + ln (b) = ln (a + 2 b) - ln (b) + ln (b)

Simplify

ln (8 a) + ln (b) = ln (a + 2 b)

Apply log rules

8 ab = a + 2 b

Solve

8 ab = a + 2 b : a = \frac{2 b}{8 b - 1}

a = \frac{2 b}{8 b - 1}

Verify Solutions:

a = \frac{2 b}{8 b - 1} {b > \frac{1}{8}}

The solution is

a = \frac{2 b}{8 b - 1} {b > \frac{1}{8}}

x, (b) \cdot y = ln (x^{2})

n = lo g_{10} (d) 150012

(lo g_{10} (x))^{2} - lo g_{10} (x) - 2 = 0

lo g_{2} (x - 1) = - 2022

(lo g_{2} (x))^{2} - 5 \cdot lo g_{2} (x) + 6 = 0

What is the answer to solvefor a,ln(8a)=ln(a+2b)-ln(b) ?
The answer to solvefor a,ln(8a)=ln(a+2b)-ln(b) is a=(2b)/(8b-1) {b> 1/8 }