What is the answer to log_{10}(x+1)=log_{10}(2x+1) ?

The answer to log_{10}(x+1)=log_{10}(2x+1) is x=0

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log_{10}(x+1)=log_{10}(2x+1)

lo g_{10} (x + 1) = lo g_{10} (2 x + 1)

x = 0

Solution steps

lo g_{10} (x + 1) = lo g_{10} (2 x + 1)

Apply log rules

x + 1 = 2 x + 1

Solve

x + 1 = 2 x + 1 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

lo g_{10} (x + 2) - lo g_{10} (x - 1) = 4

x^{1 + l o g_{10} (x)} = 10 x

(lo g_{10} (x))^{2} = lo g_{10} (x^{2})

2 lo g_{10} (x) - lo g_{10} (x + 6) = 0

ln (\frac{1}{x}) + ln (2 x^{3}) = ln^{3} (x)

What is the answer to log_{10}(x+1)=log_{10}(2x+1) ?
The answer to log_{10}(x+1)=log_{10}(2x+1) is x=0
Solve for x: log_{10}(x+1)=log_{10}(2x+1)
The solution is x=0