What is the answer to 2log_{10}(x)-log_{10}(x+6)=0 ?

The answer to 2log_{10}(x)-log_{10}(x+6)=0 is x=3

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2log_{10}(x)-log_{10}(x+6)=0

2 lo g_{10} (x) - lo g_{10} (x + 6) = 0

x = 3

Solution steps

2 lo g_{10} (x) - lo g_{10} (x + 6) = 0

Apply log rules

x^{2} = x + 6

Solve

x^{2} = x + 6 : x = 3, x = - 2

x = 3, x = - 2

Verify Solutions:

x = 3

True

, x = - 2

False

The solution is

x = 3

ln (\frac{1}{x}) + ln (2 x^{3}) = ln^{3} (x)

2 lo g_{10} (x) + 1 = lo g_{250} (x)

lo g_{10} (x) - 4 (\frac{1 - x}{2}) = 1

ln (2 x + 1) - ln (x - 6) = 0

lo g_{10} (x) = 5

What is the answer to 2log_{10}(x)-log_{10}(x+6)=0 ?
The answer to 2log_{10}(x)-log_{10}(x+6)=0 is x=3
Solve for x: 2log_{10}(x)-log_{10}(x+6)=0
The solution is x=3