What is the answer to 2log_{10}(x)+1=log_{250}(x) ?

The answer to 2log_{10}(x)+1=log_{250}(x) is x= 1/(250^{(log_{250)(10))/(2-log_{250)(10)}}}

Solve for x: 2log_{10}(x)+1=log_{250}(x)

The solution is x= 1/(250^{(log_{250)(10))/(2-log_{250)(10)}}}

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2 lo g_{10} (x) + 1 = lo g_{250} (x)

x = \frac{1}{25 0 ^{\frac{l o g _{250} ( 10 )}{2 - l o g _{250} ( 10 )}}}

Decimal Notation

x = 0.23349 \dots

Solution steps

2 lo g_{10} (x) + 1 = lo g_{250} (x)

Apply log rules

x = \frac{1}{25 0 ^{\frac{l o g _{250} ( 10 )}{2 - l o g _{250} ( 10 )}}}

Verify Solutions:

x = \frac{1}{25 0 ^{\frac{l o g _{250} ( 10 )}{2 - l o g _{250} ( 10 )}}}

True

The solution is

x = \frac{1}{25 0 ^{\frac{l o g _{250} ( 10 )}{2 - l o g _{250} ( 10 )}}}

lo g_{10} (x) - 4 (\frac{1 - x}{2}) = 1

ln (2 x + 1) - ln (x - 6) = 0

lo g_{10} (x) = 5

lo g_{2} (2 x + 7) = 4

lo g_{5} (x) = 1 + lo g_{10} (x^{25})

What is the answer to 2log_{10}(x)+1=log_{250}(x) ?
The answer to 2log_{10}(x)+1=log_{250}(x) is x= 1/(250^{(log_{250)(10))/(2-log_{250)(10)}}}
Solve for x: 2log_{10}(x)+1=log_{250}(x)
The solution is x= 1/(250^{(log_{250)(10))/(2-log_{250)(10)}}}