What is the answer to ln(x^2-3)=4 ?

The answer to ln(x^2-3)=4 is x=sqrt(e^4+3),x=-sqrt(e^4+3)

Solve for x: ln(x^2-3)=4

The solution is x=sqrt(e^4+3),x=-sqrt(e^4+3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

ln (x^{2} - 3) = 4

x = e^{4} + 3, x = - e^{4} + 3

Decimal Notation

x = 7.58934 \dots, x = - 7.58934 \dots

Solution steps

ln (x^{2} - 3) = 4

Apply log rules

x^{2} - 3 = e^{4}

Solve

x^{2} - 3 = e^{4} : x = e^{4} + 3, x = - e^{4} + 3

x = e^{4} + 3, x = - e^{4} + 3

lo g_{17} (x^{3} + 2 x^{2} - x + 15) = 1

lo g_{4} (22 - 4 x) = 2

lo g_{2} (x^{5}) = lo g_{10} (2 x)^{4}

lo g_{5} (x^{2}) - 4 = 2 + ∣ lo g_{5} (x) - 3 ∣

lo g_{2} (x^{2}) = 8

What is the answer to ln(x^2-3)=4 ?
The answer to ln(x^2-3)=4 is x=sqrt(e^4+3),x=-sqrt(e^4+3)
Solve for x: ln(x^2-3)=4
The solution is x=sqrt(e^4+3),x=-sqrt(e^4+3)