What is the answer to 6.27=-log_{10}(h) ?

The answer to 6.27=-log_{10}(h) is h=5.37032E-7

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6.27=-log_{10}(h)

6.27 = - lo g_{10} (h)

h = 5.37032 E - 7

Solution steps

6.27 = - lo g_{10} (h)

Move

lo g_{10} (h)

to the left side

6.27 + lo g_{10} (h) = 0

Move

6.27

to the right side

lo g_{10} (h) = - 6.27

Apply log rules

h = 5.37032 E - 7

Verify Solutions:

h = 5.37032 E - 7

True

The solution is

h = 5.37032 E - 7

ln (y) = 2

lo g_{10} (100 x) = \frac{1}{2}

lo g_{2} (x - 1) + lo g_{3} (3) = 2

lo g_{10} (x) + lo g_{10} (x + 7) = 8

lo g_{3} (3 x + 1) - lo g_{3} (x - 1) = 4

What is the answer to 6.27=-log_{10}(h) ?
The answer to 6.27=-log_{10}(h) is h=5.37032E-7
Solve for h: 6.27=-log_{10}(h)
The solution is h=5.37032E-7