What is the answer to log_{10}(x-2)+log_{10}(x+2)=2 ?

The answer to log_{10}(x-2)+log_{10}(x+2)=2 is x=2sqrt(26)

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log_{10}(x-2)+log_{10}(x+2)=2

lo g_{10} (x - 2) + lo g_{10} (x + 2) = 2

x = 226

Decimal Notation

x = 10.19803 \dots

Solution steps

lo g_{10} (x - 2) + lo g_{10} (x + 2) = 2

Apply log rules

(x - 2) (x + 2) = 100

Solve

(x - 2) (x + 2) = 100 : x = 226, x = - 226

x = 226, x = - 226

Verify Solutions:

x = 226

True

, x = - 226

False

The solution is

x = 226

73 = 18 lo g_{10} (\frac{17.176}{x})

lo g_{10} (4 x + 6) = 2

lo g_{4} (8) + lo g_{4} (x + 3) - lo g_{4} (x - 1) = 2

lo g_{3} (3^{x} - 6) = x - 1

8 ln (x^{2}) = x

What is the answer to log_{10}(x-2)+log_{10}(x+2)=2 ?
The answer to log_{10}(x-2)+log_{10}(x+2)=2 is x=2sqrt(26)
Solve for x: log_{10}(x-2)+log_{10}(x+2)=2
The solution is x=2sqrt(26)