What is the answer to log_{22}(2x)-5log_{2}(x)=0 ?

The answer to log_{22}(2x)-5log_{2}(x)=0 is x= 1/(22^{(log_{22)(2)^2)/(log_{22)(2)-5}}}

Solve for x: log_{22}(2x)-5log_{2}(x)=0

The solution is x= 1/(22^{(log_{22)(2)^2)/(log_{22)(2)-5}}}

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lo g_{22} (2 x) - 5 lo g_{2} (x) = 0

x = \frac{1}{2 2 ^{\frac{l o g _{22} ( 2 ) ^{2}}{l o g _{22} ( 2 ) - 5}}}

Decimal Notation

x = 1.03308 \dots

Solution steps

lo g_{22} (2 x) - 5 lo g_{2} (x) = 0

Apply log rules

x = \frac{1}{2 2 ^{\frac{l o g _{22} ( 2 ) ^{2}}{l o g _{22} ( 2 ) - 5}}}

Verify Solutions:

x = \frac{1}{2 2 ^{\frac{l o g _{22} ( 2 ) ^{2}}{l o g _{22} ( 2 ) - 5}}}

True

The solution is

x = \frac{1}{2 2 ^{\frac{l o g _{22} ( 2 ) ^{2}}{l o g _{22} ( 2 ) - 5}}}

lo g_{10} (x + 2) + lo g_{10} (x - 2) = 1

ln (8 - 2 x) = \frac{1}{2} ln (4 - x)

ln (x) = 3.47

lo g_{3} (2 x + 7) = 2

ln (x^{3}) - 4 ln (x) = 1

What is the answer to log_{22}(2x)-5log_{2}(x)=0 ?
The answer to log_{22}(2x)-5log_{2}(x)=0 is x= 1/(22^{(log_{22)(2)^2)/(log_{22)(2)-5}}}
Solve for x: log_{22}(2x)-5log_{2}(x)=0
The solution is x= 1/(22^{(log_{22)(2)^2)/(log_{22)(2)-5}}}