What is the answer to solvefor x,log_{3}(x)+log_{3}(y)=0 ?

The answer to solvefor x,log_{3}(x)+log_{3}(y)=0 is x= 1/y

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solvefor x,log_{3}(x)+log_{3}(y)=0

solve for

x, lo g_{3} (x) + lo g_{3} (y) = 0

x = \frac{1}{y}

Solution steps

lo g_{3} (x) + lo g_{3} (y) = 0

Move

lo g_{3} (y)

to the right side

lo g_{3} (x) = - lo g_{3} (y)

Apply log rules

x = \frac{1}{y}

Verify Solutions:

x = \frac{1}{y}

True

The solution is

x = \frac{1}{y}

lo g_{5} (14 x + 5) = 9

lo g_{2} (3 x - 1) = 3

m, \frac{1}{2} \cdot lo g_{3} (m) + 3 lo g_{3} (n) = 1

lo g_{5} (x) - lo g_{5} (2 x - 1) - lo g_{10} (625) = 0

lo g_{2} (3 x) = 5

What is the answer to solvefor x,log_{3}(x)+log_{3}(y)=0 ?
The answer to solvefor x,log_{3}(x)+log_{3}(y)=0 is x= 1/y