What is the answer to log_{10}(2x-2)=log_{10}(x+1) ?

The answer to log_{10}(2x-2)=log_{10}(x+1) is x=3

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log_{10}(2x-2)=log_{10}(x+1)

lo g_{10} (2 x - 2) = lo g_{10} (x + 1)

x = 3

Solution steps

lo g_{10} (2 x - 2) = lo g_{10} (x + 1)

Apply log rules

2 x - 2 = x + 1

Solve

2 x - 2 = x + 1 : x = 3

x = 3

Verify Solutions:

x = 3

True

The solution is

x = 3

2 lo g_{10} (x) - lo g_{10} (2 x + 15) = 0

lo g_{4} (m) = 0

lo g_{4} (x) = 0

lo g_{10} (10 x + 5) = lo g_{10} (9 x + 3)

lo g_{4} (x) = 6

What is the answer to log_{10}(2x-2)=log_{10}(x+1) ?
The answer to log_{10}(2x-2)=log_{10}(x+1) is x=3
Solve for x: log_{10}(2x-2)=log_{10}(x+1)
The solution is x=3