What is the answer to log_{10}(x^2)=1.7482 ?

The answer to log_{10}(x^2)=1.7482 is x=sqrt(10^{1.7482)},x=-sqrt(10^{1.7482)}

Solve for x: log_{10}(x^2)=1.7482

The solution is x=sqrt(10^{1.7482)},x=-sqrt(10^{1.7482)}

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lo g_{10} (x^{2}) = 1.7482

x = 1 0^{1.7482}, x = - 1 0^{1.7482}

Decimal Notation

x = 7.48341 \dots, x = - 7.48341 \dots

Solution steps

lo g_{10} (x^{2}) = 1.7482

Apply log rules

x^{2} = 1 0^{1.7482}

Solve

x^{2} = 1 0^{1.7482} : x = 1 0^{1.7482}, x = - 1 0^{1.7482}

x = 1 0^{1.7482}, x = - 1 0^{1.7482}

2.3 lo g_{10} (\frac{t ^{1}}{t ^{2}}) = 0.69825

lo g_{10} (1 + x) = 1 + lo g_{10} (x)

ln (x + 1) = - 2

lo g_{2} (x) - lo g_{2} (x + 1) = 3

lo g_{6} (2 x + 16) = 3

What is the answer to log_{10}(x^2)=1.7482 ?
The answer to log_{10}(x^2)=1.7482 is x=sqrt(10^{1.7482)},x=-sqrt(10^{1.7482)}
Solve for x: log_{10}(x^2)=1.7482
The solution is x=sqrt(10^{1.7482)},x=-sqrt(10^{1.7482)}