What is the answer to log_{1/2}(x^2-3)=log_{2}(x^2) ?

The answer to log_{1/2}(x^2-3)=log_{2}(x^2) is x=sqrt((3+\sqrt{13))/2},x=-sqrt((3+\sqrt{13))/2}

Solve for x: log_{1/2}(x^2-3)=log_{2}(x^2)

The solution is x=sqrt((3+\sqrt{13))/2},x=-sqrt((3+\sqrt{13))/2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

lo g_{\frac{1}{2}} (x^{2} - 3) = lo g_{2} (x^{2})

x = \frac{3 + 13}{2}, x = - \frac{3 + 13}{2}

Decimal Notation

x = 1.81735 \dots, x = - 1.81735 \dots

Solution steps

lo g_{\frac{1}{2}} (x^{2} - 3) = lo g_{2} (x^{2})

Apply log rules

1 = x^{2} (x^{2} - 3)

Solve

1 = x^{2} (x^{2} - 3) : x = \frac{3 + 13}{2}, x = - \frac{3 + 13}{2}

x = \frac{3 + 13}{2}, x = - \frac{3 + 13}{2}

Verify Solutions:

x = \frac{3 + 13}{2}

True

, x = - \frac{3 + 13}{2}

True

The solutions are

x = \frac{3 + 13}{2}, x = - \frac{3 + 13}{2}

u, lo g_{u} (\frac{15}{16}) = v

ln (x) = \frac{1}{2}

140 = 20 lo g_{10} (\frac{75000}{x})

x = ln (9 - x)

lo g_{3} ((2 + x)^{2}) = 6

What is the answer to log_{1/2}(x^2-3)=log_{2}(x^2) ?
The answer to log_{1/2}(x^2-3)=log_{2}(x^2) is x=sqrt((3+\sqrt{13))/2},x=-sqrt((3+\sqrt{13))/2}
Solve for x: log_{1/2}(x^2-3)=log_{2}(x^2)
The solution is x=sqrt((3+\sqrt{13))/2},x=-sqrt((3+\sqrt{13))/2}