What is the answer to x=ln(sqrt(9-x)) ?

The answer to x=ln(sqrt(9-x)) is x=-(\W_{0}(2e^{18})-18)/2

Solve for x: x=ln(sqrt(9-x))

The solution is x=-(\W_{0}(2e^{18})-18)/2

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x = ln (9 - x)

x = - \frac{W _{0} ( 2 e ^{18} ) - 18}{2}

Decimal Notation

x = 1.03737 \dots

Solution steps

x = ln (9 - x)

f (x) = g (x),

then

a^{f (x)} = a^{g (x)}

e^{x} = e^{l n (9 - x)}

Simplify

e^{l n (9 - x)} : 9 - x

e^{x} = 9 - x

Solve

e^{x} = 9 - x : x = - \frac{W _{0} ( 2 e ^{18} ) - 18}{2}

x = - \frac{W _{0} ( 2 e ^{18} ) - 18}{2}

Verify Solutions:

x = - \frac{W _{0} ( 2 e ^{18} ) - 18}{2}

True

The solution is

x = - \frac{W _{0} ( 2 e ^{18} ) - 18}{2}

lo g_{3} ((2 + x)^{2}) = 6

lo g_{3} (x - 5) + lo g_{3} (x + 2) = lo g_{3} (8)

lo g_{10} (x) + lo g_{10} (x + 3) = 2 lo g_{10} (x + 1)

x, (lo g_{2} (x))^{2} = \frac{1}{f}

2 lo g_{10} (x) = 3 + lo g_{10} (x)

What is the answer to x=ln(sqrt(9-x)) ?
The answer to x=ln(sqrt(9-x)) is x=-(\W_{0}(2e^{18})-18)/2
Solve for x: x=ln(sqrt(9-x))
The solution is x=-(\W_{0}(2e^{18})-18)/2