What is the answer to log_{3}(x-5)+log_{3}(x+2)=log_{3}(8) ?

The answer to log_{3}(x-5)+log_{3}(x+2)=log_{3}(8) is x=6

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log_{3}(x-5)+log_{3}(x+2)=log_{3}(8)

lo g_{3} (x - 5) + lo g_{3} (x + 2) = lo g_{3} (8)

x = 6

Solution steps

lo g_{3} (x - 5) + lo g_{3} (x + 2) = lo g_{3} (8)

Apply log rules

(x - 5) (x + 2) = 8

Solve

(x - 5) (x + 2) = 8 : x = 6, x = - 3

x = 6, x = - 3

Verify Solutions:

x = 6

True

, x = - 3

False

The solution is

x = 6

lo g_{10} (x) + lo g_{10} (x + 3) = 2 lo g_{10} (x + 1)

x, (lo g_{2} (x))^{2} = \frac{1}{f}

2 lo g_{10} (x) = 3 + lo g_{10} (x)

lo g_{10} (10 m) = 4

lo g_{5} (x^{2} + x + 5) = 2

What is the answer to log_{3}(x-5)+log_{3}(x+2)=log_{3}(8) ?
The answer to log_{3}(x-5)+log_{3}(x+2)=log_{3}(8) is x=6
Solve for x: log_{3}(x-5)+log_{3}(x+2)=log_{3}(8)
The solution is x=6