What is the answer to log_{3}(log_{2}(x+9))=1 ?

The answer to log_{3}(log_{2}(x+9))=1 is x=-1

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log_{3}(log_{2}(x+9))=1

lo g_{3} (lo g_{2} (x + 9)) = 1

x = - 1

Solution steps

lo g_{3} (lo g_{2} (x + 9)) = 1

Apply log rules

x + 9 = 8

Solve

x + 9 = 8 : x = - 1

x = - 1

Verify Solutions:

x = - 1

True

The solution is

x = - 1

ln (x^{2}) = 2 ln (x)

lo g_{16} (x) = \frac{3}{4}

b, ln (12 b) = 2 ln (b + 3 a) - ln (a)

\frac{lo g _{10} ( 80 )}{lo g _{10} ( 2 x )} = \frac{lo g _{10} ( 500 )}{lo g _{10} ( 5 x )}

lo g_{5} ((x - 2)^{2}) \cdot lo g_{2} (5) = 2

What is the answer to log_{3}(log_{2}(x+9))=1 ?
The answer to log_{3}(log_{2}(x+9))=1 is x=-1
Solve for x: log_{3}(log_{2}(x+9))=1
The solution is x=-1