What is the answer to solvefor a,log_{3}(a)+1=2log_{10}(9)(b) ?

The answer to solvefor a,log_{3}(a)+1=2log_{10}(9)(b) is a=3^{4log_{10}(3)b-1}

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solvefor a,log_{3}(a)+1=2log_{10}(9)(b)

solve for

a, lo g_{3} (a) + 1 = 2 lo g_{10} (9) (b)

a = 3^{4 l o g_{10} (3) b - 1}

Solution steps

lo g_{3} (a) + 1 = 2 lo g_{10} (9) (b)

Move

1

to the right side

lo g_{3} (a) = 2 lo g_{10} (9) b - 1

Apply log rules

a = 3^{4 l o g_{10} (3) b - 1}

Verify Solutions:

a = 3^{4 l o g_{10} (3) b - 1}

True

The solution is

a = 3^{4 l o g_{10} (3) b - 1}

lo g_{10} (x + 2) - lo g_{10} (9) = lo g_{10} (15)

lo g_{10} (x) = - 1

lo g_{10} (x) = - 5

lo g_{3} (5 x - 4) = 3

2 lo g_{10} (x) = lo g_{2} (x)

What is the answer to solvefor a,log_{3}(a)+1=2log_{10}(9)(b) ?
The answer to solvefor a,log_{3}(a)+1=2log_{10}(9)(b) is a=3^{4log_{10}(3)b-1}