What is the answer to log_{5}(2x+3)=log_{5}(x+2) ?

The answer to log_{5}(2x+3)=log_{5}(x+2) is x=-1

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log_{5}(2x+3)=log_{5}(x+2)

lo g_{5} (2 x + 3) = lo g_{5} (x + 2)

x = - 1

Solution steps

lo g_{5} (2 x + 3) = lo g_{5} (x + 2)

Apply log rules

2 x + 3 = x + 2

Solve

2 x + 3 = x + 2 : x = - 1

x = - 1

Verify Solutions:

x = - 1

True

The solution is

x = - 1

lo g_{6} (x + 5) = 3

lo g_{7} (x) = 4

lo g_{2} (x - 4^{2}) = 4

(lo g_{10} (x))^{2} - lo g_{10} (x^{2}) - 3 = 0

a, lo g_{3} (a) + 1 = 2 lo g_{10} (b)

What is the answer to log_{5}(2x+3)=log_{5}(x+2) ?
The answer to log_{5}(2x+3)=log_{5}(x+2) is x=-1
Solve for x: log_{5}(2x+3)=log_{5}(x+2)
The solution is x=-1