What is the answer to log_{2}(4x+5)=log_{2}(9-2x) ?

The answer to log_{2}(4x+5)=log_{2}(9-2x) is x= 2/3

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log_{2}(4x+5)=log_{2}(9-2x)

lo g_{2} (4 x + 5) = lo g_{2} (9 - 2 x)

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

lo g_{2} (4 x + 5) = lo g_{2} (9 - 2 x)

Apply log rules

4 x + 5 = 9 - 2 x

Solve

4 x + 5 = 9 - 2 x : x = \frac{2}{3}

x = \frac{2}{3}

Verify Solutions:

x = \frac{2}{3}

True

The solution is

x = \frac{2}{3}

ln (x - 2) = x + 1

lo g_{10} (8 x) = \frac{11}{16}

lo g_{2} (x - l) = 2 \cdot lo g_{2} (x - 3)

lo g_{3} (x - 4) = 2

9 lo g_{3} (4 x - 6) = lo g_{3} (x)

What is the answer to log_{2}(4x+5)=log_{2}(9-2x) ?
The answer to log_{2}(4x+5)=log_{2}(9-2x) is x= 2/3
Solve for x: log_{2}(4x+5)=log_{2}(9-2x)
The solution is x= 2/3