What are the solutions to the equation y^2+8y+15=0 ?

The solutions to the equation y^2+8y+15=0 are y=-3,y=-5

Find the zeros of y^2+8y+15=0

The zeros of y^2+8y+15=0 are y=-3,y=-5

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y^{2} + 8 y + 15 = 0

y = - 3, y = - 5

Solution steps

y^{2} + 8 y + 15 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 15 = 2

y_{1, 2} = \frac{- 8 \pm 2}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 8 + 2}{2 \cdot 1}, y_{2} = \frac{- 8 - 2}{2 \cdot 1}

y = \frac{- 8 + 2}{2 \cdot 1} : - 3

y = \frac{- 8 - 2}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

y = - 3, y = - 5

8 x^{2} - 72 = 0

1 0^{2 x + 7} > 100 0^{x}

∣ 4 x - 3 ∣ = ∣ x + 14 ∣

25 x + 11 = - 6 x^{2}

50 < 5 x - 5 (\frac{x - 10}{2}) \leq 100

What are the solutions to the equation y^2+8y+15=0 ?
The solutions to the equation y^2+8y+15=0 are y=-3,y=-5
Find the zeros of y^2+8y+15=0
The zeros of y^2+8y+15=0 are y=-3,y=-5