What are the solutions to the equation 25x+11=-6x^2 ?

The solutions to the equation 25x+11=-6x^2 are x=-11/3 ,x=-1/2

Find the zeros of 25x+11=-6x^2

The zeros of 25x+11=-6x^2 are x=-11/3 ,x=-1/2

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25 x + 11 = - 6 x^{2}

x = - \frac{11}{3}, x = - \frac{1}{2}

Solution steps

25 x + 11 = - 6 x^{2}

Switch sides

- 6 x^{2} = 25 x + 11

Move

11

to the left side

- 6 x^{2} - 11 = 25 x

Move

25 x

to the left side

- 6 x^{2} - 11 - 25 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 x^{2} - 25 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 25 ) \pm ( - 25 ) ^{2} - 4 ( - 6 ) ( - 11 )}{2 ( - 6 )}

(- 25)^{2} - 4 (- 6) (- 11) = 19

x_{1, 2} = \frac{- ( - 25 ) \pm 19}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- ( - 25 ) + 19}{2 ( - 6 )}, x_{2} = \frac{- ( - 25 ) - 19}{2 ( - 6 )}

x = \frac{- ( - 25 ) + 19}{2 ( - 6 )} : - \frac{11}{3}

x = \frac{- ( - 25 ) - 19}{2 ( - 6 )} : - \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{11}{3}, x = - \frac{1}{2}

50 < 5 x - 5 (\frac{x - 10}{2}) \leq 100

16 n^{8} - 24 n^{4} p - 7 p^{2}

a^{2} - 10 a + 5 = - 4

q^{\frac{3}{2}}

What are the solutions to the equation 25x+11=-6x^2 ?
The solutions to the equation 25x+11=-6x^2 are x=-11/3 ,x=-1/2
Find the zeros of 25x+11=-6x^2
The zeros of 25x+11=-6x^2 are x=-11/3 ,x=-1/2