What is 41x+37y=77,47x+51y=99 ?

The solution to 41x+37y=77,47x+51y=99 is x= 3/4 ,y= 5/4

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41x+37y=77,47x+51y=99

41 x + 37 y = 77, 47 x + 51 y = 99

x = \frac{3}{4}, y = \frac{5}{4}

Solution steps

[41 x + 37 y = 77 47 x + 51 y = 99]

Isolate

x

for

41 x + 37 y = 77 : x = \frac{77 - 37 y}{41}

Substitute

x = \frac{77 - 37 y}{41}

[47 \cdot \frac{77 - 37 y}{41} + 51 y = 99]

Simplify

[\frac{3619 + 352 y}{41} = 99]

Isolate

y

for

\frac{3619 + 352 y}{41} = 99 : y = \frac{5}{4}

For

x = \frac{77 - 37 y}{41}

Substitute

y = \frac{5}{4}

x = \frac{77 - 37 \cdot \frac{5}{4}}{41}

\frac{77 - 37 \cdot \frac{5}{4}}{41} = \frac{3}{4}

x = \frac{3}{4}

The solutions to the system of equations are:

x = \frac{3}{4}, y = \frac{5}{4}

x - 2 y = 8, 2 x + y = 6

3 x + 2 y = - 1, 5 x + y = 4

2 x + 3 y = 2, - 5 x + 12 y = 1

x - y = 14, 3 x + 2 y = 22

4 (2 x + y) + 5 (2 x - y) = 17, 3 (2 x + y) - (2 x - y) = 8

What is 41x+37y=77,47x+51y=99 ?
The solution to 41x+37y=77,47x+51y=99 is x= 3/4 ,y= 5/4