What is y+2x-19=0,2x-3y+3=0 ?

The solution to y+2x-19=0,2x-3y+3=0 is x= 27/4 ,y= 11/2

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y+2x-19=0,2x-3y+3=0

y + 2 x - 19 = 0, 2 x - 3 y + 3 = 0

x = \frac{27}{4}, y = \frac{11}{2}

Solution steps

[y + 2 x - 19 = 0 2 x - 3 y + 3 = 0]

Isolate

y

for

y + 2 x - 19 = 0 : y = - 2 x + 19

Substitute

y = - 2 x + 19

[2 x - 3 (- 2 x + 19) + 3 = 0]

Simplify

[8 x - 54 = 0]

Isolate

x

for

8 x - 54 = 0 : x = \frac{27}{4}

For

y = - 2 x + 19

Substitute

x = \frac{27}{4}

y = - 2 \cdot \frac{27}{4} + 19

- 2 \cdot \frac{27}{4} + 19 = \frac{11}{2}

y = \frac{11}{2}

The solutions to the system of equations are:

x = \frac{27}{4}, y = \frac{11}{2}

2 x - y = 3, 3 x + 2 y = 8

2 x + y = 8, x - 4 y = - 5

5 x - 2 y = 2, - x - 2 y = - 10

x + 2 y - 3 z = 4, y + 2 z = 3, z = 1

5 x - y = 3, 2 x + 4 y = - 12

What is y+2x-19=0,2x-3y+3=0 ?
The solution to y+2x-19=0,2x-3y+3=0 is x= 27/4 ,y= 11/2