What is 5x-4y=-1,0y=2x-5 ?

The solution to 5x-4y=-1,0y=2x-5 is x= 5/2 ,y= 27/8

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5x-4y=-1,0y=2x-5

5 x - 4 y = - 1, 0 y = 2 x - 5

x = \frac{5}{2}, y = \frac{27}{8}

Solution steps

[5 x - 4 y = - 1 0 \cdot y = 2 x - 5]

Isolate

x

for

5 x - 4 y = - 1 : x = \frac{- 1 + 4 y}{5}

Substitute

x = \frac{- 1 + 4 y}{5}

[0 \cdot y = 2 \cdot \frac{- 1 + 4 y}{5} - 5]

Simplify

[0 = \frac{2 ( - 1 + 4 y )}{5} - 5]

Isolate

y

for

0 = \frac{2 ( - 1 + 4 y )}{5} - 5 : y = \frac{27}{8}

For

x = \frac{- 1 + 4 y}{5}

Substitute

y = \frac{27}{8}

x = \frac{- 1 + 4 \cdot \frac{27}{8}}{5}

\frac{- 1 + 4 \cdot \frac{27}{8}}{5} = \frac{5}{2}

x = \frac{5}{2}

The solutions to the system of equations are:

x = \frac{5}{2}, y = \frac{27}{8}

y = 3 x - 5, 2 x - y + 1 = 0

2 x - 3 y + 2 = 0, 6 x + 9 y + 5 = 0

7 m + 13 n = 27, 13 m + 7 n = 33

5 x + 7 y = - 1, - 3 x + 4 y = - 24

2 x - 3 y = 5, x + y = 10