What is 2x+3y=4,-2x+4y+z=3 ?

The solution to 2x+3y=4,-2x+4y+z=3 is x=(3z+7}{14},y=\frac{-z+7)/7

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2x+3y=4,-2x+4y+z=3

2 x + 3 y = 4, - 2 x + 4 y + z = 3

x = \frac{3 z + 7}{14}, y = \frac{- z + 7}{7}

Solution steps

[2 x + 3 y = 4 - 2 x + 4 y + z = 3]

Isolate

x

for

2 x + 3 y = 4 : x = \frac{4 - 3 y}{2}

Substitute

x = \frac{4 - 3 y}{2}

[- 2 \cdot \frac{4 - 3 y}{2} + 4 y + z = 3]

Simplify

[- 4 + 7 y + z = 3]

Isolate

y

for

- 4 + 7 y + z = 3 : y = \frac{- z + 7}{7}

For

x = \frac{4 - 3 y}{2}

Expressing

x

in terms of

z

x = \frac{4 - 3 \cdot \frac{- z + 7}{7}}{2}

Simplify

\frac{4 - 3 \cdot \frac{- z + 7}{7}}{2} : \frac{3 z + 7}{14}

x = \frac{3 z + 7}{14}

The solutions to the system of equations are:

x = \frac{3 z + 7}{14}, y = \frac{- z + 7}{7}

5 x + 3 y = 21, x + 2 y = 12

2 \frac{x}{a} + \frac{y}{b} = 2, \frac{x}{a} - \frac{y}{b} = 4

5 x + y = 4, x = 2 y + 3

\frac{( x + 3 )}{2} - \frac{( y - 1 )}{3} = 1, \frac{( x + y )}{5} = 1

f (y, x, h) y = 2, 3 x - 53 h y = - 1, 4 x + 23 j y = 23 x - 113

What is 2x+3y=4,-2x+4y+z=3 ?
The solution to 2x+3y=4,-2x+4y+z=3 is x=(3z+7}{14},y=\frac{-z+7)/7