What is x/2+y/3 =1, x/3+y/2 =1 ?

The solution to x/2+y/3 =1, x/3+y/2 =1 is x= 6/5 ,y= 6/5

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x/2+y/3 =1, x/3+y/2 =1

\frac{x}{2} + \frac{y}{3} = 1, \frac{x}{3} + \frac{y}{2} = 1

x = \frac{6}{5}, y = \frac{6}{5}

Solution steps

[\frac{x}{2} + \frac{y}{3} = 1 \frac{x}{3} + \frac{y}{2} = 1]

Isolate

x

for

\frac{x}{2} + \frac{y}{3} = 1 : x = 2 - \frac{2 y}{3}

Substitute

x = 2 - \frac{2 y}{3}

[\frac{2 - \frac{2 y}{3}}{3} + \frac{y}{2} = 1]

Simplify

[\frac{12 + 5 y}{18} = 1]

Isolate

y

for

\frac{12 + 5 y}{18} = 1 : y = \frac{6}{5}

For

x = 2 - \frac{2 y}{3}

Substitute

y = \frac{6}{5}

x = 2 - \frac{2 \cdot \frac{6}{5}}{3}

2 - \frac{2 \cdot \frac{6}{5}}{3} = \frac{6}{5}

x = \frac{6}{5}

The solutions to the system of equations are:

x = \frac{6}{5}, y = \frac{6}{5}

x + 2 y = 3, + y = 2 x + 5

\frac{x}{3} + \frac{y}{4} = 2, 3 x + 4 y = 25

2 x + y = 4, 3 x + y = 5

- 17 x + 13 y = 43, 13 x - 17 y = - 47

5 x + 7 y = 1, 6 \cdot 3 x + 8 y = 12

What is x/2+y/3 =1, x/3+y/2 =1 ?
The solution to x/2+y/3 =1, x/3+y/2 =1 is x= 6/5 ,y= 6/5