What is x-y+3=2,x+3y-4=0 ?

The solution to x-y+3=2,x+3y-4=0 is x= 1/4 ,y= 5/4

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x-y+3=2,x+3y-4=0

x - y + 3 = 2, x + 3 y - 4 = 0

x = \frac{1}{4}, y = \frac{5}{4}

Solution steps

[x - y + 3 = 2 x + 3 y - 4 = 0]

Isolate

x

for

x - y + 3 = 2 : x = y - 1

Substitute

x = y - 1

[y - 1 + 3 y - 4 = 0]

Simplify

[4 y - 5 = 0]

Isolate

y

for

4 y - 5 = 0 : y = \frac{5}{4}

For

x = y - 1

Substitute

y = \frac{5}{4}

x = \frac{5}{4} - 1

\frac{5}{4} - 1 = \frac{1}{4}

x = \frac{1}{4}

The solutions to the system of equations are:

x = \frac{1}{4}, y = \frac{5}{4}

x + y = 4, x - y = 8

32 a + 6 b = 27 + 9, - 2 a - 7 b = 9

x + y = 4, x - y = 6

15 x + 4 y = 35, 100 x - 9 y = 90

x = 7, y = 2