What is 1/3*x+y= 10/3 ,2x+1/4*y= 11/4 ?

The solution to 1/3*x+y= 10/3 ,2x+1/4*y= 11/4 is x=1,y=3

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1/3x+y= 10/3 ,2x+1/4y= 11/4

\frac{1}{3} \cdot x + y = \frac{10}{3}, 2 x + \frac{1}{4} \cdot y = \frac{11}{4}

x = 1, y = 3

Solution steps

[\frac{1}{3} x + y = \frac{10}{3} 2 x + \frac{1}{4} y = \frac{11}{4}]

Isolate

x

for

\frac{1}{3} \cdot x + y = \frac{10}{3} : x = 10 - 3 y

Substitute

x = 10 - 3 y

[2 (10 - 3 y) + \frac{1}{4} y = \frac{11}{4}]

Simplify

[20 - \frac{23}{4} y = \frac{11}{4}]

Isolate

y

for

20 - \frac{23}{4} y = \frac{11}{4} : y = 3

For

x = 10 - 3 y

Substitute

y = 3

x = 10 - 3 \cdot 3

Simplify

x = 1

The solutions to the system of equations are:

x = 1, y = 3

f (x) = x^{3} + 1, x^{0} = 1

3 y - x = 5, 2 y + x = - 10

x + y + z = 1, 2 x - 2 y + z = 3, - 3 x + y + 2 z = 0

\frac{1}{2} \cdot x + \frac{1}{3} \cdot y = 3, x + \frac{1}{2} \cdot y = 5

- \frac{1}{8} \cdot x + y = \frac{33}{4}, - \frac{1}{9} \cdot x - \frac{1}{10} \cdot y = - \frac{47}{30}

What is 1/3*x+y= 10/3 ,2x+1/4*y= 11/4 ?
The solution to 1/3*x+y= 10/3 ,2x+1/4*y= 11/4 is x=1,y=3