What is 3x+2y=2,2-x+4y=2 ?

The solution to 3x+2y=2,2-x+4y=2 is x= 4/7 ,y= 1/7

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3x+2y=2,2-x+4y=2

3 x + 2 y = 2, 2 - x + 4 y = 2

x = \frac{4}{7}, y = \frac{1}{7}

Solution steps

[3 x + 2 y = 2 2 - x + 4 y = 2]

Isolate

x

for

3 x + 2 y = 2 : x = \frac{2 - 2 y}{3}

Substitute

x = \frac{2 - 2 y}{3}

[2 - \frac{2 - 2 y}{3} + 4 y = 2]

Simplify

[\frac{- 2 + 14 y}{3} + 2 = 2]

Isolate

y

for

\frac{- 2 + 14 y}{3} + 2 = 2 : y = \frac{1}{7}

For

x = \frac{2 - 2 y}{3}

Substitute

y = \frac{1}{7}

x = \frac{2 - 2 \cdot \frac{1}{7}}{3}

\frac{2 - 2 \cdot \frac{1}{7}}{3} = \frac{4}{7}

x = \frac{4}{7}

The solutions to the system of equations are:

x = \frac{4}{7}, y = \frac{1}{7}

3 x + 4 y = 14, \frac{( x - y )}{2} - \frac{( 6 x + 9 y )}{10} = - 3

3 x + 4 y = 84, 5 x + 3 y = 96

2 x + 3 y = - 8, 3 x - y = - 10

2 u + 5 v + 1 = 0, u - 2 v + 9 = 0

x + y + 3 z = 1, 2 x + y + 2 z = 3, 3 x + 2 y + 5 z = 3