What is 2u+5v+1=0,u-2v+9=0 ?

The solution to 2u+5v+1=0,u-2v+9=0 is u=-47/9 ,v= 17/9

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2u+5v+1=0,u-2v+9=0

2 u + 5 v + 1 = 0, u - 2 v + 9 = 0

u = - \frac{47}{9}, v = \frac{17}{9}

Solution steps

[2 u + 5 v + 1 = 0 u - 2 v + 9 = 0]

Isolate

u

for

2 u + 5 v + 1 = 0 : u = \frac{- 5 v - 1}{2}

Substitute

u = \frac{- 5 v - 1}{2}

[\frac{- 5 v - 1}{2} - 2 v + 9 = 0]

Simplify

[\frac{- 9 v - 1}{2} + 9 = 0]

Isolate

v

for

\frac{- 9 v - 1}{2} + 9 = 0 : v = \frac{17}{9}

For

u = \frac{- 5 v - 1}{2}

Substitute

v = \frac{17}{9}

u = \frac{- 5 \cdot \frac{17}{9} - 1}{2}

\frac{- 5 \cdot \frac{17}{9} - 1}{2} = - \frac{47}{9}

u = - \frac{47}{9}

The solutions to the system of equations are:

u = - \frac{47}{9}, v = \frac{17}{9}

x + y + 3 z = 1, 2 x + y + 2 z = 3, 3 x + 2 y + 5 z = 3

35 x - 30 y + 12 = 0, 30 x + 35 y - 10 = 0

3 x - 4 y + 24 = 0, x + y - 13 = 0

2 x - y = 4, x + y = 5

3 x + y = 3, 4 x - 3 y = 17

What is 2u+5v+1=0,u-2v+9=0 ?
The solution to 2u+5v+1=0,u-2v+9=0 is u=-47/9 ,v= 17/9