What is 5x+4y=4,x-20=20y ?

The solution to 5x+4y=4,x-20=20y is x= 20/13 ,y=-12/13

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5x+4y=4,x-20=20y

5 x + 4 y = 4, x - 20 = 20 y

x = \frac{20}{13}, y = - \frac{12}{13}

Solution steps

[5 x + 4 y = 4 x - 20 = 20 y]

Isolate

x

for

5 x + 4 y = 4 : x = \frac{4 - 4 y}{5}

Substitute

x = \frac{4 - 4 y}{5}

[\frac{4 - 4 y}{5} - 20 = 20 y]

Isolate

y

for

\frac{4 - 4 y}{5} - 20 = 20 y : y = - \frac{12}{13}

For

x = \frac{4 - 4 y}{5}

Substitute

y = - \frac{12}{13}

x = \frac{4 - 4 ( - \frac{12}{13} )}{5}

\frac{4 - 4 ( - \frac{12}{13} )}{5} = \frac{20}{13}

x = \frac{20}{13}

The solutions to the system of equations are:

x = \frac{20}{13}, y = - \frac{12}{13}

x + 2 y = 10, 4 x - 2 y = 5

5 a^{5} = 62, 5 n = 3, a^{4} = 12

2 x + y = - 6, 3 x - 2 y = 4

3 x + 5 y = 34, 2 x - y = 1

2 x - y = 3, x^{2} - y^{2} = 3

What is 5x+4y=4,x-20=20y ?
The solution to 5x+4y=4,x-20=20y is x= 20/13 ,y=-12/13