What is 2x-y=3,x^2-y^2=3 ?

The solution to 2x-y=3,x^2-y^2=3 is

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2x-y=3,x^2-y^2=3

2 x - y = 3, x^{2} - y^{2} = 3

(x = 2, y = 1)

Solution steps

[2 x - y = 3 x^{2} - y^{2} = 3]

Isolate

x

for

2 x - y = 3 : x = \frac{3 + y}{2}

Plug the solutions

x = \frac{3 + y}{2}

into

x^{2} - y^{2} = 3

For

x^{2} - y^{2} = 3

, subsitute

x

with

\frac{3 + y}{2} : y = 1

Plug the solutions

y = 1

into

2 x - y = 3

For

2 x - y = 3

, subsitute

y

with

1 : x = 2

Verify solutions by plugging them into the original equations

Therefore, the final solution for

2 x - y = 3, x^{2} - y^{2} = 3

(x = 2, y = 1)

2 x - y = 4, - 3 x + 2 y = - 5

3 x + 3 y = 12, 2 x - 2 y = 4

2 x - 3 y = 15, 3 x + 3 y = 40

5 y + 3 x = 7, 4 x - 2 y = - 8

x + 3 y = 6, x - y = 2