What is 2x-y-z=2,x+y=3,x-y+z=2 ?

The solution to 2x-y-z=2,x+y=3,x-y+z=2 is x=2,y=1,z=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2x-y-z=2,x+y=3,x-y+z=2

2 x - y - z = 2, x + y = 3, x - y + z = 2

x = 2, y = 1, z = 1

Solution steps

2 x - y - z = 2 x + y = 3 x - y + z = 2

Isolate

x

for

x + y = 3 : x = 3 - y

Substitute

x = 3 - y

[2 (3 - y) - y - z = 2 3 - y - y + z = 2]

Simplify

[6 - 3 y - z = 2 3 - 2 y + z = 2]

Isolate

y

for

6 - 3 y - z = 2 : y = - \frac{z - 4}{3}

Substitute

y = - \frac{z - 4}{3}

[3 - 2 (- \frac{z - 4}{3}) + z = 2]

Simplify

[\frac{5 z - 8}{3} + 3 = 2]

Isolate

z

for

\frac{5 z - 8}{3} + 3 = 2 : z = 1

For

y = - \frac{z - 4}{3}

Substitute

z = 1

y = - \frac{1 - 4}{3}

- \frac{1 - 4}{3} = 1

y = 1

For

x = 3 - y

Substitute

y = 1, z = 1

x = 3 - 1

Simplify

x = 2

The solutions to the system of equations are:

x = 2, y = 1, z = 1

y + 1 = 2, (x - 1) ey - 1 = x + 1

3 x + y = 1, (2 k - 1) x + (k - 1) y = (2 k - 1)

2 x - y = 11, 5 x + 4 y = 1

u = (62), a = (3 - 9)

11 x - 9 y + 4 = 6, x - 5 y + 3 = 0

What is 2x-y-z=2,x+y=3,x-y+z=2 ?
The solution to 2x-y-z=2,x+y=3,x-y+z=2 is x=2,y=1,z=1