What is x/5-y/4 =0,3x+y/2 =17 ?

The solution to x/5-y/4 =0,3x+y/2 =17 is x=5,y=4

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x/5-y/4 =0,3x+y/2 =17

\frac{x}{5} - \frac{y}{4} = 0, 3 x + \frac{y}{2} = 17

x = 5, y = 4

Solution steps

[\frac{x}{5} - \frac{y}{4} = 0 3 x + \frac{y}{2} = 17]

Isolate

x

for

\frac{x}{5} - \frac{y}{4} = 0 : x = \frac{5 y}{4}

Substitute

x = \frac{5 y}{4}

[3 \cdot \frac{5 y}{4} + \frac{y}{2} = 17]

Simplify

[\frac{17 y}{4} = 17]

Isolate

y

for

\frac{17 y}{4} = 17 : y = 4

For

x = \frac{5 y}{4}

Substitute

y = 4

x = \frac{5 \cdot 4}{4}

\frac{5 \cdot 4}{4} = 5

x = 5

The solutions to the system of equations are:

x = 5, y = 4

4 x - y = 3, 2 x + 3 y = 5

3 - \frac{x}{8} = 5, \frac{x}{8} = 5 \frac{x}{2} - \frac{2}{3} (x - 4) + 5

x - 1 = 3, y - 2 = 9

3 x - y - \frac{3}{5} = 6, 3 y - x - \frac{2}{7} = 9

x - y = 4, \frac{( x - y )}{( y + x )} = \frac{2}{5}

What is x/5-y/4 =0,3x+y/2 =17 ?
The solution to x/5-y/4 =0,3x+y/2 =17 is x=5,y=4