What is a*x+3y=6,2x+y=-3 ?

The solution to a*x+3y=6,2x+y=-3 is x=(15)/(-6+a),y=(-3a-12)/(-6+a),\quad a\ne 6,a\ne 0

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a*x+3y=6,2x+y=-3

a \cdot x + 3 y = 6, 2 x + y = - 3

x = \frac{15}{- 6 + a}, y = \frac{- 3 a - 12}{- 6 + a}, a \neq = 6, a \neq = 0

Solution steps

[a x + 3 y = 6 2 x + y = - 3]

Isolate

x

for

a \cdot x + 3 y = 6 : x = \frac{6 - 3 y}{a}; a \neq = 0

Substitute

x = \frac{6 - 3 y}{a}

[2 \cdot \frac{6 - 3 y}{a} + y = - 3]

Simplify

[\frac{2 ( 6 - 3 y )}{a} + y = - 3]

Isolate

y

for

\frac{2 ( 6 - 3 y )}{a} + y = - 3 : y = \frac{- 3 a - 12}{- 6 + a}; a \neq = 0, a \neq = 6

For

x = \frac{6 - 3 y}{a}

Substitute

y = \frac{- 3 a - 12}{- 6 + a}

x = \frac{6 - 3 \cdot \frac{- 3 a - 12}{- 6 + a}}{a}

Simplify

\frac{6 - 3 \cdot \frac{- 3 a - 12}{- 6 + a}}{a} : \frac{15}{- 6 + a}

x = \frac{15}{- 6 + a}

The solutions to the system of equations are:

x = \frac{15}{- 6 + a}, y = \frac{- 3 a - 12}{- 6 + a}, a \neq = 6, a \neq = 0

3 x - 7 y = - 13, - 4 x + y = - 16

4 x + 3 y = 1, 8 x - 3 y = 7

- 2 i w (z) = - 5 i, z = 4

5 x + 10 y = 29, 0 x + y = 35

3 x + y = 8, x + 2 y = 6

What is a*x+3y=6,2x+y=-3 ?
The solution to a*x+3y=6,2x+y=-3 is x=(15)/(-6+a),y=(-3a-12)/(-6+a),\quad a\ne 6,a\ne 0