What are the solutions to the equation 2x^2+10x-72=0 ?

The solutions to the equation 2x^2+10x-72=0 are x=4,x=-9

Find the zeros of 2x^2+10x-72=0

The zeros of 2x^2+10x-72=0 are x=4,x=-9

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2 x^{2} + 10 x - 72 = 0

x = 4, x = - 9

Solution steps

2 x^{2} + 10 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 2 ( - 72 )}{2 \cdot 2}

1 0^{2} - 4 \cdot 2 (- 72) = 26

x_{1, 2} = \frac{- 10 \pm 26}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 10 + 26}{2 \cdot 2}, x_{2} = \frac{- 10 - 26}{2 \cdot 2}

x = \frac{- 10 + 26}{2 \cdot 2} : 4

x = \frac{- 10 - 26}{2 \cdot 2} : - 9

The solutions to the quadratic equation are:

x = 4, x = - 9

3 a^{2} b + 6 a b^{2} - 9 b^{3}

\frac{1}{2} - \frac{3}{5}

\frac{1.01 - 2}{( 1.01 - 1 ) ^{2}}

e^{0}

4 t^{2} - 3 t - 3 = 0

What are the solutions to the equation 2x^2+10x-72=0 ?
The solutions to the equation 2x^2+10x-72=0 are x=4,x=-9
Find the zeros of 2x^2+10x-72=0
The zeros of 2x^2+10x-72=0 are x=4,x=-9