What is x-y+1=3,x+2y-12=0 ?

The solution to x-y+1=3,x+2y-12=0 is x= 16/3 ,y= 10/3

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x-y+1=3,x+2y-12=0

x - y + 1 = 3, x + 2 y - 12 = 0

x = \frac{16}{3}, y = \frac{10}{3}

Solution steps

[x - y + 1 = 3 x + 2 y - 12 = 0]

Isolate

x

for

x - y + 1 = 3 : x = y + 2

Substitute

x = y + 2

[y + 2 + 2 y - 12 = 0]

Simplify

[3 y - 10 = 0]

Isolate

y

for

3 y - 10 = 0 : y = \frac{10}{3}

For

x = y + 2

Substitute

y = \frac{10}{3}

x = \frac{10}{3} + 2

\frac{10}{3} + 2 = \frac{16}{3}

x = \frac{16}{3}

The solutions to the system of equations are:

x = \frac{16}{3}, y = \frac{10}{3}

x - 2 - 4 - 3 - 2235 y = - 2 x - 4, y = 2

2 x - 3 y - 3 = 0, \frac{( 2 x )}{3} + 4 y + \frac{1}{2} = 0

2 x - 3 y = 0, 3 x - 8 y = 0

y = 7 x, x + y = 8

15 x + 17 y = 21, 17 x + 15 y = 17

What is x-y+1=3,x+2y-12=0 ?
The solution to x-y+1=3,x+2y-12=0 is x= 16/3 ,y= 10/3