What is 10x+8y=6,e^4x-9y=161 ?

The solution to 10x+8y=6,e^4x-9y=161 is

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10x+8y=6,e^4x-9y=161

10 x + 8 y = 6, e^{4} x - 9 y = 161

(x = \frac{671}{4 e ^{4} + 45}, y = \frac{805 - 3 e ^{4}}{- 4 e ^{4} - 45})

Solution steps

[10 x + 8 y = 6 e^{4} x - 9 y = 161]

Isolate

x

for

10 x + 8 y = 6 : x = \frac{3 - 4 y}{5}

Plug the solutions

x = \frac{3 - 4 y}{5}

into

e^{4} x - 9 y = 161

For

e^{4} x - 9 y = 161

, subsitute

x

with

\frac{3 - 4 y}{5} : y = \frac{805 - 3 e ^{4}}{- 4 e ^{4} - 45}

Plug the solutions

y = \frac{805 - 3 e ^{4}}{- 4 e ^{4} - 45}

into

10 x + 8 y = 6

For

10 x + 8 y = 6

, subsitute

y

with

\frac{805 - 3 e ^{4}}{- 4 e ^{4} - 45} : x = \frac{671}{4 e ^{4} + 45}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

10 x + 8 y = 6, e^{4} x - 9 y = 161

(x = \frac{671}{4 e ^{4} + 45}, y = \frac{805 - 3 e ^{4}}{- 4 e ^{4} - 45})

3 x - 7 y + 10 = 0, y - 2 x - 3 = 0

r = 0, s = 0

2 x - 8 y + 3 z = 1, - x + 2 y - 3 z = - 2

x + y = 2, x - y = - 6

x - 10 y = 2, y = 4