What is 2x-y=12, 3/2 x+5y=4 ?

The solution to 2x-y=12, 3/2 x+5y=4 is x= 128/23 ,y=-20/23

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2x-y=12, 3/2 x+5y=4

2 x - y = 12, \frac{3}{2} x + 5 y = 4

x = \frac{128}{23}, y = - \frac{20}{23}

Solution steps

[2 x - y = 12 \frac{3}{2} x + 5 y = 4]

Isolate

x

for

2 x - y = 12 : x = \frac{12 + y}{2}

Substitute

x = \frac{12 + y}{2}

[\frac{3}{2} \cdot \frac{12 + y}{2} + 5 y = 4]

Simplify

[\frac{36 + 23 y}{4} = 4]

Isolate

y

for

\frac{36 + 23 y}{4} = 4 : y = - \frac{20}{23}

For

x = \frac{12 + y}{2}

Substitute

y = - \frac{20}{23}

x = \frac{12 - \frac{20}{23}}{2}

\frac{12 - \frac{20}{23}}{2} = \frac{128}{23}

x = \frac{128}{23}

The solutions to the system of equations are:

x = \frac{128}{23}, y = - \frac{20}{23}

x + 2 y + z = 3, 2 x - 3 y + 2 z = - 15, 3 x + 6 y - 7 z = 59

- 3 x + 5 y = 2, 7 x - 3 y = 1

19 x + 3 y = 5, 2 x + y = (r + 1)

3 x + 2 y = 8, x + 3 y = 5

4 x - y = 0, 3 x + 2 y = 12

What is 2x-y=12, 3/2 x+5y=4 ?
The solution to 2x-y=12, 3/2 x+5y=4 is x= 128/23 ,y=-20/23