What are the solutions to the equation x^3+8x^2+19x+12=0,x=-4 ?

The solutions to the equation x^3+8x^2+19x+12=0,x=-4 are x=-4

Find the zeros of x^3+8x^2+19x+12=0,x=-4

The zeros of x^3+8x^2+19x+12=0,x=-4 are x=-4

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x^{3} + 8 x^{2} + 19 x + 12 = 0, x = - 4

x = - 4

Solution steps

x^{3} + 8 x^{2} + 19 x + 12 = 0

Factor

x^{3} + 8 x^{2} + 19 x + 12 : (x + 1) (x + 3) (x + 4)

(x + 1) (x + 3) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 3 = 0 or x + 4 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 3 = 0 : x = - 3

Solve

x + 4 = 0 : x = - 4

The solutions are

x = - 1, x = - 3, x = - 4

Check constrains

x = - 4

6 x - 3 y = - 1, 3 x + 5 y - 8 = 0

x + 2 y - 4 = 2, x + 4 y - 6 = 0

3 x - 5 y = 20, 6 x - 10 y = - 40

y = \frac{1}{x ^{2}} - x, x = 2, x = 3

x + y + z = 11, 0 x + 2 y + 3 z = 25, 4 x + 5 y + 7 z = 800

What are the solutions to the equation x^3+8x^2+19x+12=0,x=-4 ?
The solutions to the equation x^3+8x^2+19x+12=0,x=-4 are x=-4
Find the zeros of x^3+8x^2+19x+12=0,x=-4
The zeros of x^3+8x^2+19x+12=0,x=-4 are x=-4