What is x+y=3,2x-1=4(3-y) ?

The solution to x+y=3,2x-1=4(3-y) is x=-1/2 ,y= 7/2

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x+y=3,2x-1=4(3-y)

x + y = 3, 2 x - 1 = 4 (3 - y)

x = - \frac{1}{2}, y = \frac{7}{2}

Solution steps

[x + y = 3 2 x - 1 = 4 (3 - y)]

Isolate

x

for

x + y = 3 : x = 3 - y

Substitute

x = 3 - y

[2 (3 - y) - 1 = 4 (3 - y)]

Simplify

[- 2 y + 5 = 4 (3 - y)]

Isolate

y

for

- 2 y + 5 = 4 (3 - y) : y = \frac{7}{2}

For

x = 3 - y

Substitute

y = \frac{7}{2}

x = 3 - \frac{7}{2}

3 - \frac{7}{2} = - \frac{1}{2}

x = - \frac{1}{2}

The solutions to the system of equations are:

x = - \frac{1}{2}, y = \frac{7}{2}

\frac{1}{q} 1 = 30, 0 q^{2} = 200, p^{1} = 8, p^{2} = 1

\frac{2}{x} + \frac{2}{y} = \frac{1}{6}, \frac{3}{x} + \frac{2}{y} = 0

3 x + y = - 1, x - y = 5

b = - 5, a = 1

2 x + y - 6 = 4, x - 2 y - 4 = 0