What is x+4y-z=12,3x+8y-2z=4 ?

The solution to x+4y-z=12,3x+8y-2z=4 is x=-20,y=-(-z-32)/4

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x+4y-z=12,3x+8y-2z=4

x + 4 y - z = 12, 3 x + 8 y - 2 z = 4

x = - 20, y = - \frac{- z - 32}{4}

Solution steps

[x + 4 y - z = 12 3 x + 8 y - 2 z = 4]

Isolate

x

for

x + 4 y - z = 12 : x = 12 - 4 y + z

Substitute

x = 12 - 4 y + z

[3 (12 - 4 y + z) + 8 y - 2 z = 4]

Simplify

[- 4 y + z + 36 = 4]

Isolate

y

for

- 4 y + z + 36 = 4 : y = - \frac{- z - 32}{4}

For

x = 12 - 4 y + z

Expressing

x

in terms of

z

x = 12 - 4 (- \frac{- z - 32}{4}) + z

12 - 4 (- \frac{- z - 32}{4}) + z = - 20

x = - 20

The solutions to the system of equations are:

x = - 20, y = - \frac{- z - 32}{4}

(2) x - 3 y = 1, 3 x - 2 y + 4 = 0

x + 2 y = 5, 3 x - y = 1

x + y - 2 z = 9, 2 x - y + 4 z = 4, 2 x - y + 6 z = - 1

x = y, x = 0, y = 3

3 x - y - 4 = 0, 4 x + y - 17 = 0

What is x+4y-z=12,3x+8y-2z=4 ?
The solution to x+4y-z=12,3x+8y-2z=4 is x=-20,y=-(-z-32)/4