What are the solutions to the equation -3x^2-15+12x=0 ?

The solutions to the equation -3x^2-15+12x=0 are x=2-i,x=2+i

Find the zeros of -3x^2-15+12x=0

The zeros of -3x^2-15+12x=0 are x=2-i,x=2+i

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- 3 x^{2} - 15 + 12 x = 0

x = 2 - i, x = 2 + i

Solution steps

- 3 x^{2} - 15 + 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} + 12 x - 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) ( - 15 )}{2 ( - 3 )}

Simplify

1 2^{2} - 4 (- 3) (- 15) : 6 i

x_{1, 2} = \frac{- 12 \pm 6 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 12 + 6 i}{2 ( - 3 )}, x_{2} = \frac{- 12 - 6 i}{2 ( - 3 )}

x = \frac{- 12 + 6 i}{2 ( - 3 )} : 2 - i

x = \frac{- 12 - 6 i}{2 ( - 3 )} : 2 + i

The solutions to the quadratic equation are:

x = 2 - i, x = 2 + i

(x - 8) (x - 2) (x + 4) \leq 0

n^{2} - 81

2 x^{2} + 11 x - 4 = 2

0.25 x + 35 = 0.15 x + 50

x + 1 = - 5

What are the solutions to the equation -3x^2-15+12x=0 ?
The solutions to the equation -3x^2-15+12x=0 are x=2-i,x=2+i
Find the zeros of -3x^2-15+12x=0
The zeros of -3x^2-15+12x=0 are x=2-i,x=2+i