What is 6/x+4/y =3, 9/x-1/y = 23/4 ?

The solution to 6/x+4/y =3, 9/x-1/y = 23/4 is

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6/x+4/y =3, 9/x-1/y = 23/4

\frac{6}{x} + \frac{4}{y} = 3, \frac{9}{x} - \frac{1}{y} = \frac{23}{4}

(x = \frac{21}{13}, y = - \frac{28}{5})

Solution steps

[\frac{6}{x} + \frac{4}{y} = 3 \frac{9}{x} - \frac{1}{y} = \frac{23}{4}]

Isolate

x

for

\frac{6}{x} + \frac{4}{y} = 3 : x = - \frac{6 y}{4 - 3 y}; y \neq = \frac{4}{3}

Plug the solutions

x = - \frac{6 y}{4 - 3 y}

into

\frac{9}{x} - \frac{1}{y} = \frac{23}{4}

For

\frac{9}{x} - \frac{1}{y} = \frac{23}{4}

, subsitute

x

with

- \frac{6 y}{4 - 3 y} : y = - \frac{28}{5}

Plug the solutions

y = - \frac{28}{5}

into

\frac{6}{x} + \frac{4}{y} = 3

For

\frac{6}{x} + \frac{4}{y} = 3

, subsitute

y

with

- \frac{28}{5} : x = \frac{21}{13}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{6}{x} + \frac{4}{y} = 3, \frac{9}{x} - \frac{1}{y} = \frac{23}{4}

(x = \frac{21}{13}, y = - \frac{28}{5})

(v) - 5 y - 16 = 3, x + 4 y - 1 = 0

2 x - y = 3, x + y = 3

f (x) = 2, 7 f (x) = 3 x - 9

2 x + 3 y = 51, 1 x - 5 y = 6

\frac{5}{3} y = \frac{34}{3}, x = 2

What is 6/x+4/y =3, 9/x-1/y = 23/4 ?
The solution to 6/x+4/y =3, 9/x-1/y = 23/4 is