What is 3/x+1-1/y+1=7, 1/x+1-1/y+1=13 ?

The solution to 3/x+1-1/y+1=7, 1/x+1-1/y+1=13 is

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3/x+1-1/y+1=7, 1/x+1-1/y+1=13

\frac{3}{x} + 1 - \frac{1}{y} + 1 = 7, \frac{1}{x} + 1 - \frac{1}{y} + 1 = 13

(x = - \frac{1}{3}, y = - \frac{1}{14})

Solution steps

[\frac{3}{x} + 1 - \frac{1}{y} + 1 = 7 \frac{1}{x} + 1 - \frac{1}{y} + 1 = 13]

Subtract the equations

\frac{3}{x} + 1 - \frac{1}{y} + 1 = 7

\frac{3}{x} + 1 - \frac{1}{y} + 1 - (\frac{1}{x} + 1 - \frac{1}{y} + 1) = 7 - 13

Simplify

\frac{2}{x} = - 6

Solve

\frac{2}{x} = - 6 : x = - \frac{1}{3}

Plug the solutions

x = - \frac{1}{3}

into

\frac{3}{x} + 1 - \frac{1}{y} + 1 = 7

For

\frac{3}{x} + 1 - \frac{1}{y} + 1 = 7

, subsitute

x

with

- \frac{1}{3} : y = - \frac{1}{14}

Verify solutions by plugging them into the original equations

Therefore, the final solution for

\frac{3}{x} + 1 - \frac{1}{y} + 1 = 7, \frac{1}{x} + 1 - \frac{1}{y} + 1 = 13

(x = - \frac{1}{3}, y = - \frac{1}{14})

2 x + 3 y = 3, x + y = 4

2 x + 4 y = 2, - 3 x + y = 11

1 (- 3 + 5 \frac{y}{6}) - 9 y = - 4, x = 1

2 x - 3 y + 13 = 3, x - y - 3 = 0

- 6 x - y = 18, 6 x - 3 y = 6

What is 3/x+1-1/y+1=7, 1/x+1-1/y+1=13 ?
The solution to 3/x+1-1/y+1=7, 1/x+1-1/y+1=13 is