What is 2x-3y+13=3,x-y-3=0 ?

The solution to 2x-3y+13=3,x-y-3=0 is x=19,y=16

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2x-3y+13=3,x-y-3=0

2 x - 3 y + 13 = 3, x - y - 3 = 0

x = 19, y = 16

Solution steps

[2 x - 3 y + 13 = 3 x - y - 3 = 0]

Isolate

x

for

2 x - 3 y + 13 = 3 : x = \frac{3 y - 10}{2}

Substitute

x = \frac{3 y - 10}{2}

[\frac{3 y - 10}{2} - y - 3 = 0]

Simplify

[\frac{y - 10}{2} - 3 = 0]

Isolate

y

for

\frac{y - 10}{2} - 3 = 0 : y = 16

For

x = \frac{3 y - 10}{2}

Substitute

y = 16

x = \frac{3 \cdot 16 - 10}{2}

\frac{3 \cdot 16 - 10}{2} = 19

x = 19

The solutions to the system of equations are:

x = 19, y = 16

- 6 x - y = 18, 6 x - 3 y = 6

3 x + 4 y = 2, 3 y = 2 x - 8

3 x_{1} + x_{2} = - 4, 6 x_{1} + 2 x_{2} = - 8

e = 12 v, r = 5 r, i = 2 a

x + 3 y = 14, 3 x + 2 y = 21