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Popular >

1+2|x-1|<= 9

Solution

1 + 2 ∣ x - 1 ∣ \leq 9

Solution

- 3 \leq x \leq 5

+1

Interval Notation

[- 3, 5]

Solution steps

1 + 2 ∣ x - 1 ∣ \leq 9

Move

1

to the right side

2 ∣ x - 1 ∣ \leq 8

Divide both sides by

2

∣ x - 1 ∣ \leq 4

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 4 \leq x - 1 \leq 4

x - 1 \geq - 4 and x - 1 \leq 4

x \geq - 3 and x \leq 5

Merge Overlapping Intervals

- 3 \leq x \leq 5

Popular Examples

10 < 2 x - 1 \leq x + 5

2/5 x-3<(1-6x)-15<5(3-x/3)

\frac{2}{5} x - 3 < (1 - 6 x) - 15 < 5 (3 - \frac{x}{3})

- 6 + 12 x > 15 x + 4

z^{2} - 12 z = - 11

simplify ((x^2)/(y^2))^{-1}simplify

(\frac{x ^{2}}{y ^{2}})^{- 1}

Frequently Asked Questions (FAQ)

What is 1+2|x-1|<= 9 ?
The solution to 1+2|x-1|<= 9 is -3<= x<= 5