What is x= 1/3 y,y= 1/(2z) ?

The solution to x= 1/3 y,y= 1/(2z) is x= 1/(6z),y= 1/(2z)

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x= 1/3 y,y= 1/(2z)

x = \frac{1}{3} y, y = \frac{1}{2 z}

x = \frac{1}{6 z}, y = \frac{1}{2 z}

Solution steps

[x = \frac{1}{3} y y = \frac{1}{2 z}]

[y = \frac{1}{2 z}]

For

x = \frac{1}{3} y

Expressing

x

in terms of

z

x = \frac{1}{3} \cdot \frac{1}{2 z}

Simplify

\frac{1}{3} \cdot \frac{1}{2 z} : \frac{1}{6 z}

x = \frac{1}{6 z}

The solutions to the system of equations are:

x = \frac{1}{6 z}, y = \frac{1}{2 z}

x + 5 y = 1, 6 x + 3 y = 10

4 x - 5 y - 20 = 0, 3 x + 5 y - 15 = 0

x + y = 14, 2 x + 2 y = 8

2 x + 3 y = 8, 7 x - 3 y = 1

(\frac{1}{x} - y) + (\frac{1}{x} + y) = 6, (\frac{1}{x} - y) - (\frac{1}{x} + y) = 4

What is x= 1/3 y,y= 1/(2z) ?
The solution to x= 1/3 y,y= 1/(2z) is x= 1/(6z),y= 1/(2z)